Table of Contents
Measurements and Experimentation Solutions Exercise 1(B) — Very Short Answer Type
Exercise 1(B) — Very Short Answer Type
Ans: Least count of an instrument is the smallest measurement that can be taken accurately with it.
Ans: The least count can be decreased by:
- Increasing the number of divisions on the vernier scale
- Decreasing the value of one division on main scale
Ans: The difference between one main scale division and one vernier scale division. Also known as least count of vernier.
Ans: When zero marks of both scales coincide with jaws closed, and 10th vernier division aligns with 9th main scale division.
Ans:
- External diameter → Outside jaws
- Internal diameter → Inside jaws
- Depth → Strip
- Thickness → Outer jaws
Ans:
- Positive: Vernier zero right of main scale zero
- Negative: Vernier zero left of main scale zero
Ans: The linear distance moved by the screw on the main scale when the circular scale completes one full rotation.
Ans: Measuring diameter of thin wires or thickness of thin sheets.
Ans: To prevent over-tightening and ensure consistent pressure during measurements.
Ans:
- Positive: Circular scale zero below reference line
- Negative: Circular scale zero above reference line
Ans:
- Needle diameter → Screw gauge
- Paper thickness → Screw gauge
- Bottle neck → Vernier calipers
- Pencil diameter → Screw gauge
Ans: Screw gauge (0.01 mm accuracy)
Ans:
Least Count | Instrument |
---|---|
0.1 mm | Vernier Calipers |
1 mm | Metre Rule |
0.01 mm | Screw Gauge |
Exercise 1(A) — Multiple Choice Type
Exercise 1(A) — Very Short Answer Type
Exercise 1(A) — Short Answer Type
Exercise 1(B) — Multiple Choice Type
Exercise 1(B) — Very Short Answer Type
Exercise 1(B) — Short Answer Type
Exercise 1(B) — Long Answer Type
Exercise 1(B) — Numericals
Exercise 1(C) — Multiple Choice Type
Exercise 1(C) — Very Short Answer Type
Exercise 1(C) — Short Answer Type
Exercise 1(C) — Long Answer Type
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